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0=2x^2-20x+350
We move all terms to the left:
0-(2x^2-20x+350)=0
We add all the numbers together, and all the variables
-(2x^2-20x+350)=0
We get rid of parentheses
-2x^2+20x-350=0
a = -2; b = 20; c = -350;
Δ = b2-4ac
Δ = 202-4·(-2)·(-350)
Δ = -2400
Delta is less than zero, so there is no solution for the equation
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